What does x=randint(1,1,[1,n]); ?

What does x=randint(1,1,[1,n]); ?

Answer 1

[M]

I may be wrong, but I think randint was part of the Communication System Toolbox and its functionality has been replaced by the randi function, for which you can find details here .

[Walter Roberson]

Correct. randint(1,1,[1,n]) would now be written as randi([1,n],1,1)

[Jenny]

Thank you.

Answer 2

[pankaj singh]

Please note that randint is an obsolete function in the Matlab. You can use randi instead.

randint generates the matrix of uniformly distributed random integers. e.g.

out = randint(M,N);

generates M-by-N matrix of random binary numbers, i.e., 0 and 1 occur with equal probability.

Your example is similar to

out = randint(M,N,[IRANGE(1), IRANGE(2)]]);

where an M-by-N matrix is generated and the elements of the matrix will be in the range mentioned in the square brackets.

Therefore,

x=randint(1,1,[1,n]);

will generate a 1-by-1 matrix or just a number within the range [1, n], where n can be any integer.

Answer 3

[DHRUVIN SUTHAR]

Hi, I wanted to genrate the single random value in between 5 to 10 and I am trying to use randint function as a randi but I getting an error. could anyone please suggest me any idea?

x =randi(1,1,[5,10]); but I am getting an error "Error using randi;

Size inputs must be scalar."

[Walter Roberson]

As I said,

"randint(1,1,[1,n]) would now be written as randi([1,n],1,1)"

You left the parameters in the same order. You would need randi([5 10], 1, 1)

[DHRUVIN SUTHAR]

Thank you so much for your quick responce. It worked.

[pankaj singh]

What does this will generate?

randint(1,ndata*col,M)

[Walter Roberson]

@pankaj singh

randint(1,ndata*col,M)

would return a 1 x (ndata*col) row vector in which each element was an integer in the range [0 M-1]

The more modern equivalent would be

randi([0 M-1], 1, ndata*col)

[pankaj singh]

Thanks a lot

Answer 4

[Zeeshan Ahmad]

Randint is no more working, you have to use randi but it will make difference,

like if you are writing randint(9600,1)

now for randi you have to write randi(1,9600)

[Walter Roberson]

to replace randint(9600,1) you would use randi([0,1],9600,1)

[Zeeshan Ahmad]

bother let take a example. randi(1,9600) will generate the data of 9600x9600

and randi(9600,1) will give you any single value, (between 0-9600) for example on first run it gate me 5860

now to come to your point.

your ans was correct as "randint(1,1,[1,n]) would now be written as randi([1,n],1,1)"

i was just giving an example to new people who take code from mathworks and cant run it in advance versions.

[Walter Roberson]

randi(9600,1) will give you any single value, (between 0-9600)

This is a difference between randi and randint. randi(9600,1) would give you a single value in the range 1 to 9600, whereas randint(9600,1) would give you 9600 values in the range 0 to 1, and randint(1,1,9600) would give you a single value in the range 0 to 9599, but randint(1,1,[1 9600]) would give you a single value in the range 1 to 9600.