how to slove this problem?

sir ,I write a code but the final ans E contain two different matrix array size that is the combination of both E2 and k2 .I cannot convert into a single binary matrix. The binary sequence is converted into 24 integers in which each one is produced by 8 binary bits.please execute the code and if you find any different idea please inform me as soon as possible.

if true
 clc;
clear all;
close all;
img = imread('cameraman.tif');
c=img';
d=c(:);
[W,L]=size(img);
k=randi(192,1,192);
syms k1 t 
for i=1:4
  k1=k(((48*i)-47):(48*i));
  a1 = symsum(k1*(2^(t-(48*i)+47)),t,((48*i)-47),(48*i));
  a=a1/(2^48);
end
for x=1:2
r(x)=mod(prod(a*(2^48)+a(x)),0.4)+3.6;
C(x)=mod(prod(a*(2^48)+a(x+2)),1);
end
C1=C(1);
C2=C(2);
for y=1:[W,L]
if y==1
  C(y)=C(x);
else
  if y~=1&&C(y-1)<0.5
  C(y)=0.5*(r(x)*C(y-1));
  else
      if y~=1&&C(y-1)>=0.5
  C(y)=0.5*(r(x)*(1-(C(y-1))));
     end
  end
end
end
for y=1:[W,L]
  if y==1
      E1(y)=d(y);
  else
      E1(y)=mod(d(y)+floor(C(y)*(10^13))+d(y-1),256);   
  end
end
for y=1:[W,L]
  if y==[W,L]
      E2(y)=E1(y);
  else
      E2(y)=mod(E1(y)+floor(C(y)*(10^13))+E1(y+1),256);
  end
end
E2=E2';
Q=sum(E2');
Q=sym2poly(Q); 
for j=1:192
q=dec2bin(Q,j);
kb=dec2bin(k,j);
end
kb = kb(randi(size(kb,1)),:);
k2=xor(q,kb);
E=[1,(W*L)+24];
E={k2,E2}

%E=bin2dec(char('0'+reshape(bits, 8, 24).'))

end