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change the element-by-element organization into a plane organization

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Claudia
Claudia on 15 May 2012
Hello
I have an array <20000x1 struct> in element-by-element organization. Each of the 20000 entries has more than 30 fields.
I would like to change the element-by-element organization into a plane organization.
I found how to do it from plane to element-by-element ( http://www.mathworks.com/matlabcentral/answers/4581-deleting-the-i-th-entry-from-all-fields-of-a-struct) but I cannot figure out how to do it in the opposite way.
Could you help me, please?
Thank you very much
Claudia
  1 Comment
Claudia
Claudia on 8 Nov 2012
long time ago I found my own solution but forgot to put it here. So, here it is:
folder = ['/scratch ...']
fields = fieldnames (datastructold) ;
for f = 1:size(fields,1) ;
varname = genvarname(fields{f}) ;
extract = {datastructold.(varname)};
datastructnew.(varname) = extract ;
end
v = genvarname([ 'name' ]) % name for variable
S.(v) = datastructnew
save([ folder v '.mat' ] , '-struct' , 'S' ) ; % name for .mat

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Accepted Answer

Claudia
Claudia on 29 Jan 2013
long time ago I found my own solution but forgot to put it here. So, here it is:
folder = ['/scratch ...']
fields = fieldnames (datastructold) ;
for f = 1:size(fields,1) ;
varname = genvarname(fields{f}) ;
extract = {datastructold.(varname)};
datastructnew.(varname) = extract ;
end
v = genvarname([ 'name' ]) % name for variable
S.(v) = datastructnew
save([ folder v '.mat' ] , '-struct' , 'S' ) ; % name for .mat

More Answers (2)

Walter Roberson
Walter Roberson on 15 May 2012
struct2cell(), then either cell2mat() or expand the cell within a vertcat() or horzcat().
However, if the fields are not all exactly the same size or are of mixed numeric type involving more than one integer data type, then you are going to have problems.
  1 Comment
Claudia
Claudia on 18 May 2012
Hi Walter
Thank you for your answer. I tried what you suggested.
But for cell2mat all contents of the input cell array must be of the same data type.
And vertcat() and horzcat() did not change anything at all.
So, at the end I missed the step to get the structure with plane organization.
It would be nice if you could explain that step.
Thanks, Claudia

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Sean de Wolski
Sean de Wolski on 8 Nov 2012
Edited: Sean de Wolski on 8 Nov 2012
So if this is a simple example of your struct:
S = struct('field1',num2cell(1:10),'field2',num2cell(repmat(pi,1,10)))
Then I would recommend using:
S2 = squeeze(struct2cell(S))
To now have a 2x10 cell array.

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