Why I get Reference to a cleared variable x. in my code?

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function data=surface_point(x,y)
clc, clear all, close all
px = [0 50 100 150 200 250 300; 0 50 100 150 200 250 300; 0 50 100 150 200 250 300; 0 50 100 150 200 250 300];
py = [0 0 0 0 0 0 0; 50 50 50 50 50 50 50;100 100 100 100 100 100 100;150 150 150 150 150 150 150];
pz = [-15 70 90 -60 -40 15 40; 40 -5 -20 -40 50 30 -20; 0 -45 -30 30 40 -10 -40; -30 5 50 0 -30 -20 20];
n=size(px,1)-1;
m=size(px,2)-1;
c=30;
u = x/300;
v = y/150;
for i=1:n+1
for j=1:m+1
sx=sx+px(i,j)*B(i-1,n,u)*B(j-1,m,v);
sy=sy+py(i,j)*B(i-1,n,u)*B(j-1,m,v);
sz=sz+pz(i,j)*B(i-1,n,u)*B(j-1,m,v);
end
end
data = [sx sy sz];
  2 Comments
Stephen23
Stephen23 on 2 Mar 2018
Edited: Stephen23 on 2 Mar 2018
"Why I get Reference to a cleared variable x. in my code?"
Because for no reason at all you put
clc, clear all, close all
at the start of your function. Why use some commands in your function if you don't know what they are doing? How are these commands in any way related to the functionality of what you are writing?
NPNJ IT
NPNJ IT on 1 Apr 2020
He probably wrote this without a function wrapper and forgot to remove that line before adding the function definition, having decided to wrap that code in a call.

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Accepted Answer

Image Analyst
Image Analyst on 2 Mar 2018
Because, although you pass in x and y, you delete them immediately with the command
clear all
Don't do that!!! If you don't do that, x will still be there when you need to use it.

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