How to access the data point that has maximum distance using rangesearch()

Hi,

I would like to retrieve the data point which has maximum distance from the middle points. This is my code:

fData = [ 3.6 79; 1.8 54; 3.333 74 ;2.283 62; 4.533 85; 2.883 55; 4.7 88 ;3.6 85 ;1.95 51 ;4.35 85 ;1.833 54; 3.917 84; 4.2 78; 1.75 47; 4.7 83; 2.167 52; 1.75 62; 4.8 84; 1.6 52; 4.25 79; 1.8 51; 1.75 47; 3.45 78; 3.067 69; 4.533 74; 3.6 83; 1.967 55; 4.083 76; 3.85 78; 4.433 79; 4.3 73; 4.467 77; 3.367 66; 4.033 80; 3.833 74; 2.017 52; 1.867 48; 4.833 80; 1.833 59; 4.783 90 ];
[n,dim]=size(fData);
r = 0.5;

[zData, mean_array, sd_array] = zscore_rescale(fData);

idx = randsample(n,2);
X = zData(~ismember(1:n,idx),:); % Training data
Y = zData(idx,:) ;

figure('Name','Result');
plot(zData(:,1),zData(:,2),'.k');
hold on;
plot(Y(:,1),Y(:,2),'*r');
[idrx1, dist1] = rangesearch(X,Y,r,'Distance','euclidean');

          for j = 1:length(Y)
              for dn =1:length(idrx1{j})
                  if ~isempty(idrx1{j})
                     plot(X([idrx1{j}],1),X([idrx1{j}],2),'*b','MarkerSize',5,'MarkerFaceColor','b','DisplayName','Imputed Data');
                  end

              end
          end

          for j = 1:length(Y)
              c = Y(j,:);
              pos = [c-r (2*r) (2*r)];
              rectangle('Position',pos,'Curvature',[1 1])
          end
          axis square

I would appreciate if anyone could advice on how to access the data point

Answer 1

[KSSV]

Two options:

1. Use pdist and pcik the maximum distance

2. Use knnsearch requesting all the nearest neighbors, from here pick the maximum distance index.

[amj]

Dear KSSV, Thank you for your prompt comment. But , i dont want to use knnSearch or pdist/pcik because it could not search nearest data points based on radius r.Am i right?

[KSSV]

knnsearch gives you a point at minimum distance from the given point.

[amj]

It is indeed true. Can i put the limit of searching by radius in knnSearch? I dont have any experience in knnsearch