Applying a function to each row vector of a matrix

I have a function that I want to apply to each row of a 7800x784 matrix. The function returns a scalar and puts it into a 7800x1 matrix. So, each row of the first matrix is computed one by one and the output is sent to the second matrix. s and Ns are both 1x26 matrix. Following is my function:

function [ind] = naive_bayes(X, s, Ns)
  prob = zeros(1,26);
  x = 1;
  y = 1800;
  for i = 1:size(s,2)
      like = sum(X(x:y,:))/s(1,i);
      prob(1,i) = Ns(1,i) * prod((like.^X).* (1-like).^(1-X));
      x = y + 1;
      y = y +1800;
  end
   [~,ind] = max(prob);
end

Thank you!

Answer 1

[Walter Roberson]

result = arrayfun(@(ROWIDX) naive_bayes(YourArray(ROWIDX,:)), (1:size(YourArray,1)).');

However, your function has the difficulty that it uses x and y and s without those having been defined.

[Sameer Karim]

Sorry for the incomplete question, I have made the changes. how can i modify your solution to accomodate for the extra parameters?

[Walter Roberson]

result = arrayfun(@(ROWIDX) naive_bayes(YourArray(ROWIDX,:),s,Ns), (1:size(YourArray,1)).');

[Sameer Karim]

I think i messed up the transistion as naive_bayes was actually a part of my main code. I want to reorganise my question so this is the code that i initially had.

    prob = zeros(1,26);
for jj = 1:N
    for i = 1:size(s,2)
        like = sum(X(x:y,:))/s(1,i);
        prob(1,i) = Ns(1,i) * prod((like.^Xtst(jj,:)).* (1-like).^(1- Xtst(jj,:)));
        x = y + 1;
        y = y +1800;
    end
    x = 1;
    y = 1800;
    [~,ind] = max(prob);
    Cpreds(jj,1) = ind;
  end

Here Xtst is my 7800x784 array with N being 7800. X is a 48600x784 array, so sum forms a 1x784 matrix. prob is processed size(s, 2)xN times, x and y resets to its initial values after one row of Xtst is processed. Now Cpreds is my Nx1 matrix with i want to finally produce. So the previous functions was actually being applied on each row of Xtst. Since the matrix size is huge I wanted to implement it using vectorisation. Thanks in advance!