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Stop the for loop

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Adrian
Adrian on 29 May 2012
I want to stop a loop when the the modulo 26 of the determinant times a 'number', then use such 'number' to multiply the inverse of a matrix. The code is:
clc, clear;
A=input('Symmetric matrix: ');
format rat;
d=det(A)
Minv=inv(A);
M1=(Minv*d);
for i=1:100
j=mod(d*i, 26);
x=i;
if j==1, break, end
end
x
Z=round(mod((M1*x), 26))
However I can't make the for loop to stop when the value of 'j' becomes 1 and use the value of 'x' to multiply the matrix; every time the value of x is the final value of 'i', in this case 100.
  1 Comment
Oleg Komarov
Oleg Komarov on 29 May 2012
Why do you expect the modulus of d*i should ever be 1?

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Accepted Answer

Geoff
Geoff on 29 May 2012
Time for the most basic of debugging practises...
After you calculate j, put in the following line of code:
disp(j);
Now, run your loop.
I'm willing to bet that j is either always even (because d is even), or is a sufficiently fractional non-integer.
When you work out what's happening and fix it, then consider the following. From a 'performance' perspective (well, really it's about not doing unnecessary things), just save the value into x once:
x = [];
for i = 1:100
if mod(d*i,26) == 1
x = i;
break;
end
end
if isempty(x)
disp('Not found');
end
Doesn't really matter here, but it's worth getting into the habit of recognising some repeated calculations as being pointless. Call it "eco-coding". =)
  3 Comments
Geoff
Geoff on 29 May 2012
Then it's probably not _exactly_ 1. Try this:
fprintf( 'i=%d : j=%.30f\n', i, j);
You might need to test with something like:
if abs(j-1) < eps(10)
Adrian
Adrian on 29 May 2012
That was it! The only thing I had to finish so my encryption/decryption program was finished. I am just starting to learn matlab and your help is really appreciated.

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