Fourier Coefficient of the given Function

##(Given Function) f(x)=1/2(sin x + sin x) xє[-π , π]

##I obtain the bellow Fourier Coefficient of the given function .

##f(x) = 1/π Σ 2((cos(nπ)-1)/nπ)

##Now I am using the below Matlab code But I think the Fourier Coefficient or the MatLab code is wrong . Please someone check.

##MatLab code

x=linspace(-pi,pi);

f=2*((cos(x)-1)/pi);

g=abs(x);

N=10;

for i=2:N

f=f+(2*((cos(i*x)-1)/pi*(i));

end

c=f+pi/2;

figure;

plot(x,c,'r',x,g,'b')