I have tried the coding. But i don't understand what does mean idx = Igray == 0? Can someone explain it to me.

1 view (last 30 days)
if true
% code
endSeparate to RGB channel
Ir = imgcrop(:,:,1);
Ig = imgcrop(:,:,2);
Ib = imgcrop(:,:,3);
% Extract the background (black) region
Igray = rgb2gray(imgcrop);
idx = Igray == 0;
% Calculate average RGB of the region
Rave = uint8(mean(Ir(~idx)));
Gave = uint8(mean(Ig(~idx)));
Bave = uint8(mean(Ib(~idx)));

Accepted Answer

Ameer Hamza
Ameer Hamza on 12 May 2018
This code is calculating the average of RGB channels while excluding the pixels where the intensity level is zero.
The line
idx = Igray == 0;
find all the pixels in grayscale image Igray, where the intensity is 0. It will return a logical matrix idx. Since only those pixels are required where intensity level is not 0, therefore we invert the logical matrix using ~idx,
Ir(~idx)
will return all the required pixels and then using mean() find the average. See Logical Indexing here.
  4 Comments
Ameer Hamza
Ameer Hamza on 12 May 2018
Edited: Ameer Hamza on 12 May 2018
As @Walter mentioned, mean() will do average along first nonscalar dimensions. In case of 2D matrix, it will average all the columns. Either use mean2() or convert to a single column before taking average like this
Rave = uint8(mean(Ir(:)));
Gave = uint8(mean(Ig(:)));
Bave = uint8(mean(Ib(:)));
disp([Rave,Gave,Bave]);
or take mean() twice
Rave = uint8(mean(mean(Ir)));
Gave = uint8(mean(mean(Ig)));
Bave = uint8(mean(mean(Ib)));
disp([Rave,Gave,Bave]);
all will produce same output.

Sign in to comment.

More Answers (1)

KSSV
KSSV on 12 May 2018
Edited: KSSV on 12 May 2018
You need to read about logical indexing in MATLAB.
idx = Igray == 0;
The above line gives the indices of pixel zero's in the matrix data Igray.

Categories

Find more on Numeric Types in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!