How to fix this loop to get the desired output ?
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Aswin Sandirakumaran
on 23 May 2018
Commented: Majid Farzaneh
on 23 May 2018
New_Td = [4,1,1]
for t = New_Td
for b = 1:t
duplicate(b) = 0;
r(b) = 0;
fprintf('Hai from %i\n',t);
disp(duplicate);
end
end
Output I am getting look like this: ->>>> WRONG OUTPUT WHICH I AM GETTING
if true
Hai from 4
0
Hai from 4
0 0
Hai from 4
0 0 0
Hai from 4
0 0 0 0
Hai from 1
0 0 0 0
Hai from 1
0 0 0 0
end
But CORRECT OUTPUT SHOULD BE LIKE THIS:
if true
Hai from 4
0
Hai from 4
0 0
Hai from 4
0 0 0
Hai from 4
0 0 0 0
Hai from 1
0
Hai from 1
0
end
0 Comments
Accepted Answer
Majid Farzaneh
on 23 May 2018
Hi,
New_Td = [4,1,1]
for t = New_Td
duplicate=[];
for b = 1:t
duplicate(b) = 0;
r(b) = 0;
fprintf('Hai from %i\n',t);
disp(duplicate);
end
end
1 Comment
Majid Farzaneh
on 23 May 2018
At the first time for t=4, duplicate length become 4. When t become 1, duplicate length is still 4.
You should destroy duplicate and build it again after each iteration. The code above is work.
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