Error finding and graphing max values of data (Error using horzcat Dimensions of matrices being concatenated are not consistent. )
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I'm trying to graph multiple sets of .csv data and display the max value for each data set on the graph itself. This has worked for all of my data sets except for one, which I keep getting the error "Error using horzcat Dimensions of matrices being concatenated are not consistent. The following is the code I've been using for two data sets, which I have attached to the post. TEK00055 is the one with errors and TEK00057 is the one without issues.
figure;
tmd=load('TEK00055.CSV');
x=5.+tmd(:,1);
y=5.*tmd(:,2);
plot(x,y)
xlabel('Time (s)')
ylabel('disp (mm)')
indexmax = find(max(y) == y);
xmax = x(indexmax);
ymax = y(indexmax);
strmax = ['Maximum = ',num2str(ymax)];
text(xmax,ymax,strmax,'HorizontalAlignment','right');
figure;
tmd=load('TEK00057.CSV');
x=5.+tmd(:,1);
y=5.*tmd(:,2);
plot(x,y)
xlabel('Time (s)')
ylabel('disp (mm)')
indexmax = find(max(y) == y);
xmax = x(indexmax);
ymax = y(indexmax);
strmax = ['Maximum = ',num2str(ymax)];
text(xmax,ymax,strmax,'HorizontalAlignment','right');
For the TEK00057 data, a graph comes out exactly how I want, with the maximum y-value being labelled, but the TEK00055 data is giving me errors. From looking through the excel files, i can't find any major differences between the two. Any help would be appreciated.
6 Comments
Geoff Hayes
on 6 Jul 2018
Zaman - which line of code is throwing the error? Is it
strmax = ['Maximum = ',num2str(ymax)];
If it is, what is ymax? Is it a scalar or an array of more than one element?
Zaman Chini
on 6 Jul 2018
Geoff Hayes
on 6 Jul 2018
usually the full error message gives the line number of where the code is throwing the exception. If you put a breakpoint at the first line of your code and then run it, you should be able to step over each line until the exception is thrown. Which line is that?
Zaman Chini
on 6 Jul 2018
Geoff Hayes
on 9 Jul 2018
Zaman - but what are the dimensions of ymax? Perhaps there are two or more idenitcal maximum values. And so the horizontal concatenation will fail when trying to create this string. If you are unsure, then put in some code like
strmax = ['Maximum = ',num2str(ymax(1))];
so that you always grab the first element of ymax.
Zaman Chini
on 9 Jul 2018
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