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How do I read data from just first row of the cell

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this is the 3x50 cell

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madhan ravi
madhan ravi on 17 Aug 2018
@Geoff Hayes shouldn’t it be feature_vec{1,:} because it’s a cell ? Just curious.
Image Analyst
Image Analyst on 17 Aug 2018
madhan, no. Just try it and see
for row = 1 : 3
for col = 1 : 50
ca{row, col} = rand(1, 4);
end
end
row1 = ca(1,:) % Correct.
row1 = ca{1,:} % Incorrect.
The first way gives the entire row while the braces way gives only the first cell of the first row. See the FAQ on cell arrays.

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Accepted Answer

Image Analyst
Image Analyst on 17 Aug 2018
Bajdar, just specify 1 for the first index of the cell array feature_vec.
array17 = feature_vec{1, 7} % Get array contained in row 1, column 7 of the cell array.
If you want all the arrays in all the cells of row 1, then you can do:
row1 = feature_vec(1,:) % row1 is another cell array - a row vector cell array.
Here row1 is a cell array that is a row vector of 50 cells. Each of those 50 cells contains a double array. To get any particular array in a specified column, use braces. For example to get the cell in the 8th column, do
cellContents18 = row1{8}; % Contents of the 8th cell will be a double array.
If you don't understand when to use braces (to refer to contents of the cell) and parentheses (to refer to the cells themselves), then see <https://matlab.wikia.com/wiki/FAQ#What_is_a_cell_array.3F the FAQ on cell arrays.) Don't worry - granted, it's a very tricky and confusing thing that is hard for a lot of people to grasp.

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Image Analyst
Image Analyst on 19 Aug 2018
You're welcome. ?
Be sure to "Accept" the answer that helped the most. (You can only accept one).
Bajdar Nour
Bajdar Nour on 20 Aug 2018
I have 3 different types of images each type contains 50 images..all images have been saved in 3X50 cell array..I want to separate each of them independently and save each one as .dat file (like row1.dat , row2.dat ,row3.dat) { Hint1: each image is double array and 9 features have been calculated. Hint2:feature_vec is .mat file}
Image Analyst
Image Analyst on 20 Aug 2018
I don't see any reason to save/store all the images. Why are you doing that? Just process them in the loop and be done with that image.

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More Answers (2)


Adusumilli Bala Surendra
Adusumilli Bala Surendra on 24 Apr 2019
The following can help you. Try this.
z =
1×3 cell array
{3×3 double} {3×3 double} {3×3 double}
>> z{1}
ans =
0.00315 + 0.011925i 0.0008042 + 0.0071843i 0.0008042 + 0.0061306i
0.0008042 + 0.0071843i 0.00315 + 0.011925i 0.0008042 + 0.0065829i
0.0008042 + 0.0061306i 0.0008042 + 0.0065829i 0.00315 + 0.011925i
>> z{1}(1,:)
ans =
0.00315 + 0.011925i 0.0008042 + 0.0071843i 0.0008042 + 0.0061306i

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