move element in array

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darksideofthemoon101
darksideofthemoon101 on 19 Jun 2012
Commented: thiago rech on 13 Nov 2020
Hi,
I have an array of n elements, let's say for example:
[0 1 2 3 4 5]
I want to move the position of one of the elements left or right by one, let's say:
[0 1 2 4 3 5]
How can I do this? Does indexing help?
  2 Comments
Stephen23
Stephen23 on 17 Nov 2017
Just use indexing:
>> V = [0,1,2,3,4,5];
>> V([5,4]) = V([4,5])
V =
0 1 2 4 3 5
thiago rech
thiago rech on 13 Nov 2020
Wau! Thank you!

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Answers (2)

Navid Mohammadzadeh
Navid Mohammadzadeh on 17 Nov 2017
Why do not use "circshift" command?
Look: A =
1
2
3
4
5
6
7
8
9
10
Y = circshift(A,3)
Y =
8
9
10
1
2
3
4
5
6
7
  2 Comments
Stephen23
Stephen23 on 17 Nov 2017
Edited: Stephen23 on 17 Nov 2017
@Navid Mohammadzadeh: because circshift does not change the position of one element, as the example in the question shows.
thiago rech
thiago rech on 13 Nov 2020
Maybe that was not the answer he was looking for, but it helped me with something else really cool.
Thanks!

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Christoph
Christoph on 19 Jun 2012
Hi,
your problem sounds wired. For what reason do you want to switch the postion of only two elements in an array?
Nevertheless I guess indexing is the only way to switch the positon of two elements. Also you need a temporary variable to store one of the objects. My solution would look like:
X = [1 2 3 4 5]; temp = X(3); X(3) = X(4); X(4) =temp;
If you need more than one time write an function with X and i (element you want to switch) as input argument and x as outputargument.
Kind regrads, CN
  3 Comments
Christoph
Christoph on 19 Jun 2012
Hi Moon,
intresting idea. I'll try to write this function at the evening if the todays soccer game is not that interesting ;)
Christoph
Christoph on 19 Jun 2012
Just thought a further minute about your problem. I guess I would modelling mixing cards in a different way. I would divide the vector at a random position and put the first stack behind the second....that should look like this:
pos = randi([1, numberofcards-1])
stack = [stack(pos+1,end),stack(1:pos)];
put this it in a for loop and you modelled the perfect card mixer

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