how to delete specific entries (based on a condition) in an array?
40 views (last 30 days)
Show older comments
Hi I wrote a small code, which goes as follows: %start of code
a = [0 12 16 13 14 25 12 1 170 172 32 5 171]; for i = 1:length(a); if a(i) < 18 a(i) = []; end end % end of code
The intent is to eliminate those entries which have values less than 18. It gives me two errors. Error One- it doesnt execute the entire length of a, stops in between with an error message that --- ??? Attempted to access a(9); index out of bounds because numel(a)=8.
Error in ==> array_elimination at 7 if a(i) < 18 Error two- It doesnt eliminate all the entries <18, it just eliminates the alternate entries. Thats strange and makes me feel that its a bug in matlab!! Need help
0 Comments
Accepted Answer
Honglei Chen
on 28 Jun 2012
Edited: Honglei Chen
on 28 Jun 2012
You are changing a every time when you found an element less than 18, so when the iteration gets to the original array length, it is out of bound. You can achieve what you want by the following command
a(a<18) = []
More Answers (0)
See Also
Categories
Find more on Matrices and Arrays in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!