How to count NaN elements in n dimentional matrix, using counter in loop?

How to count NaN elements in n dimentional matrix, using counter in loop?

Answer 1

[madhan ravi]

Without loop:

A=rand(2,2,2); % a short example with 3D matrix
A(2,2,1)=NaN; % just insert nan values to check
A(2,2,2)=NaN;
NaNs_present=nnz(isnan(A))

With loop(not necessary though):

A=rand(2,2,2);
A(2,2,1)=NaN;
A(2,2,2)=NaN;
Result=cell(1,size(A,1));
ctr=1;
for i = 1:size(A,1)
    for j = 1:size(A,2)
        for k = 1:size(A,3)
            Result{ctr}=isnan(A(i,j,k))
                ctr=ctr+1;
        end
    end
end
NaNs_present=nnz([Result{:}])

Answer 2

[Stephen23]

Where A is your array:

cnt = 0;
for k = 1:numel(A)
    cnt = cnt+isnan(A(k));
end