Counting the unique values
1 view (last 30 days)
Show older comments
I have a values
out=
c1 c2,,,,,,,,,,,,,,,,,,,,,c5
'gene1' 'd' 'u' 'd' 'u' 'd'
'gene2' 'u' 'u' 'u' 'u' 'd'
'gene3' 'u' 'u' 'd' 'u' 'u'
'gene4' 'd' 'u' 'u' 'd' 'd'
'gene5' 'u' 'u' 'u' 'u' 'd'
'gene6' 'd' 'u' 'u' 'u' 'u'
'gene7' 'd' 'u' 'd' 'u' 'u'
Taking the first column 'c1' value for gene1 is 'd' this value must be compared with all other column if there is more than 3 same vales it should be displayed,,Only first clumn must be compared with others columns
in 1st col there are 3d's ,2nd col 4u's(since 1st col is u),3rd col
4u's,,,,,,,,,,,6&7th gene's there are only 1 ans 2 d's respectively,so it should be deleted
So i need output as
'gene1' 'd' 'u' 'd' 'u' 'd'
'gene2' 'u' 'u' 'u' 'u' 'd'
'gene3' 'u' 'u' 'd' 'u' 'u'
'gene4' 'd' 'u' 'u' 'd' 'd'
'gene5' 'u' 'u' 'u' 'u' 'd'
Pleae help
1 Comment
Accepted Answer
Freddy
on 18 Jul 2012
Hello Pat,
first idea i came up with:
A = {'','c1','c2','c3','c4','c5';
'gene1' 'd' 'u' 'd' 'u' 'd';...
'gene2' 'u' 'u' 'u' 'u' 'd';...
'gene3' 'u' 'u' 'd' 'u' 'u';...
'gene4' 'd' 'u' 'u' 'd' 'd';...
'gene5' 'u' 'u' 'u' 'u' 'd';...
'gene6' 'd' 'u' 'u' 'u' 'u';...
'gene7' 'd' 'u' 'd' 'u' 'u'};
limit = 3;
F = cell2mat(A(2:end,2:end));
A(logical([0;sum(bsxfun(@eq,F,F(:,1)),2)>=limit]),:);
Hopefully it will help you.
Freddy
1 Comment
Jan
on 18 Jul 2012
You can omit the "logical", if you use:
A([true; sum(bsxfun(@eq, F, F(:,1)), 2) >= limit], :)
More Answers (2)
Walter Roberson
on 18 Jul 2012
c1_column = 2; %looks like column 2 to me, since column 1 has gene name
match_count = arrayfun(@(K) sum(out{K,cl_column} == [out{K,c1_column+1:end}]), 1:size(out,1));
out(match_count > 3, :)
Your problem description is inconsistent about what to do if the number of matches is exactly 3. You wrote that it has to be more than 3, but your sample output includes the case where it is exactly 3.
2 Comments
Jan
on 18 Jul 2012
@Pat: Come on, I'm sure you are able to fix this typo by your own. The "1" (one) looks very similar to the "l" (lowercase L). It is your job to participate as far as possible in the solution of your problems.
Bjorn Gustavsson
on 18 Jul 2012
Pat,
I strongly suggest you change the encoding of your data! Make your variable an integer array with for example 0 for 'd' and 1 for 'u'. Then you could do something like this:
genes = [0,1,0,1,0
1 1 1 1 0
1 1 0 1 1
0 1 1 0 0];
lim4disp = 3;
genes(sum(repmat(genes(:,1),[1,size(genes,2)]) == genes,2)>=lim4disp,:)
0 Comments
See Also
Categories
Find more on Genomics and Next Generation Sequencing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!