ifft and fft problem

2 views (last 30 days)
J J
J J on 22 Jul 2012
Hi all, this is probably very trivial but I am not understanding what the source of discrepancy is:
I have a gamma distribution (h1), I take its fft and then ifft. I should get the same thing (h1), but there is a factor 2 difference. Why?
k1 = 3; theta1 = 3;
% sparse sampling
dts = 1;
ts = (0:dts:359); % time
Ts = length(ts);
fs_s = 1/dts; % sampling frequency
dfs = fs_s/Ts;
f_s = (-fs_s/2:dfs:fs_s/2-dfs); % frequency
h1_s = (1/gamma(k1)) .* (ts.^(k1-1)) .* exp(-ts/theta1)/(theta1^k1);
h1_s_FT = dts*fftshift(fft(h1_s));
h1_s_hat = abs(f_s.*ifft(ifftshift(h1_s_FT)));
figure; plot(ts,h1_s,ts,h1_s_hat,'r')
I am missing a factor 2 somewhere. Thanks.
  1 Comment
J J
J J on 22 Jul 2012
Note that the real and imaginary fft plots look correct. So I guess there is something about ifft that I am missing.

Sign in to comment.

Accepted Answer

Dr. Seis
Dr. Seis on 23 Jul 2012
Edited: Dr. Seis on 23 Jul 2012
Did you mean to use "fs_s" instead of "f_s" here:
h1_s_hat = abs(fs_s.*ifft(ifftshift(h1_s_FT)));
I guess that's why you needed ".*" instead of "*" to get it to work.

More Answers (0)

Categories

Find more on Fourier Analysis and Filtering in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!