i have a martix A, i want missing numbers in the 2nd column as i explained? any help??

A =

1 3

1 5

1 6

1 8

1 10

2 4

2 8

2 9

3 1

3 3

3 5

3 7

3 9

i want output as ROWS starting with 1 = missing numbers are 2 ,4,7,9

ROWS starting with 2 = missing numbers are 1,2 ,3,5,6,7,10

ROWS starting with 1 = missing numbers are 2,4,6,8,10

Answer 1

[madhan ravi]

Alternative:

T=array2table(A);
fun=@(x) setdiff(min(A(:,1)):max(A(:,2)),x);
C=rowfun(fun,T,...
    'GroupingVariable','A1',...
    'OutputFormat','cell');
Result=[repelem(unique(A(:,1)),cellfun(@length,C)) [C{:}]']

[M.Prasanna kumar]

Thank you very much for your reponse. i accepted your both answers

Answer 2

[TADA]

granted you always have 1:3 in the first column and values between 1 and 10 in the second:

A = [1,3; 1,5; 1,6; 1,8; 1,10; 2,4; 2,8; 2,9; 3,1; 3,3; 3,5; 3,7; 3,9]; % this is your matrix
B = [repmat([1;2;3],10,1) repmat((1:10)', 3, 1)];
C = setdiff(B,A,'rows');

This is the output:

C =

     1     1
     1     2
     1     4
     1     7
     1     9
     2     1
     2     2
     2     3
     2     5
     2     6
     2     7
     2    10
     3     2
     3     4
     3     6
     3     8
     3    10

[M.Prasanna kumar]

Thank you very much sir...

Answer 3

[madhan ravi]

The below works for n numbers in the first column:

 Min=min(A(:,2));
 Max=max(A(:,2));
 [a,b,c]=unique(A(:,1));
 B=diff(b.');
 C=mat2cell(A(:,2),[B numel(c)-sum(B)],1);
 R=cellfun(@(x) setdiff(Min:Max,x),C,'un',0);
 Result=[repelem(a,cellfun(@length,R)) [R{:}]']
 

Gives:

 Result =

     1     1
     1     2
     1     4
     1     7
     1     9
     2     1
     2     2
     2     3
     2     5
     2     6
     2     7
     2    10
     3     2
     3     4
     3     6
     3     8
     3    10

[M.Prasanna kumar]

Thank you very much sirr. it resolved my problem