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vpasolve in for loop

Asked by maedeh Gh on 19 Feb 2019
Latest activity Commented on by Etsuo Maeda on 5 Mar 2019
I Run this code and it works correctly, but I wanna stop the for loop when it gets Empty sym: 0-by-1
for p=0:10
ub= vpasolve(function==0,x,[1000*p,1000*(p+1)])
end

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1 Answer

Answer by Etsuo Maeda on 5 Mar 2019

"vpasolve" returns numerical values. Its output "ub" cannot be a sym variable. If you use "solve", you can use "isempty" and "break" for your pourpose.
syms x
for k = 1:2
out = solve(x^k + 1 == 0, x)
if isempty(out) == 1
disp('break')
break;
end
disp('in loop')
end
HTH

  2 Comments

Walter Roberson
on 5 Mar 2019
This is not quite correct. vpasolve() returns symbolic values that represent numeric values. They are sym, and when no solution is found then the empty sym can be returned.
Also there is no need to compare isempty() to 1: you can just test if isempty(out)
Etsuo Maeda on 5 Mar 2019
UUUps, thank you very much for your kind correction :-)

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