putting the answer in a matrices

I have matrix a. Then, I find which column in each row has number bigger than 1. The code is as below

a =

     5     0     0     0     0     0     0     0     0     0
     3     1     0     0     0     0     0     0     0     0
     1     2     0     0     0     0     0     0     0     0
     1     0     1     0     0     0     0     0     0     0

>> for cpart=1:size(a,1)
b=a(cpart,:);
row = find(b ~=0)
end

row =

     1


row =

     1     2


row =

     1     2


row =

     1     3

How can I put the row in a matrices ?(as shown below)

     row = [1 0
            1 2
            1 2
            1 3]

[Image Analyst]

What are you going to do if you have row? Because I'm thinking you don't even need it and whatever you're going to do can be done much easier with a mask

mask = a~=0;  % Create a logical 2-D matrix.

So I don't want to tell you how to get row if it just makes things more complicated for what you eventually want to do. So, what will you do with row if you had it?

Answer 1

[Jan]

With a loop:

nA     = (a ~= 0);
nRow   = size(a, 1);
nCol   = max(sum(nA, 2));
result = zeros(nRow, nCol);  % Pre-allocation
for c = 1:nRow
    v = find(nA(c, :));
    result(c, 1:numel(v)) = v;
end

Answer 2

[madhan ravi]

 b=arrayfun(@(x)find(a(x,:)),1:size(a,1),'un',0);
 M=max(cellfun('prodofsize',b));
 C=cellfun(@(x)[x zeros(1,M-numel(x))],b,'un',0);
 Result=vertcat(C{:})

[madhan ravi]

To remove rows with all zeros:

 Result(sum(Result,2)~=0,:)