Create cell array from 00.00 to 23.59

Hi everyone,

i need to create a cell array containing time values from 00.00 to 23.59 with a step of 1 minute.

00.00

00.01

00.02

..

00.59

01.00

01.01

..

..

23.59

Just to explain it better,

t_iniz_proc=datetime(2018,2,5,0,0,0);
t_end_proc=datetime(2018,2,5,23,59,0);
DataArray=(t_iniz_proc:minutes(1):t_end_proc)'

i need something like that but i don't want to include the data, just the time in format 'hh.mm'

Can anyone help me?

Thanks a lot!

Fabio

[KALYAN ACHARJYA]

With a step of 1 minute....means?

[Fabio Pulcini]

each time in the array should be 1 minute later than the previous one.

[KALYAN ACHARJYA]

That menas 0.00 >>i min Gap>>0.01>>1 Min wait.....upto 23.59

Is this you are asking, if yes then it takes much longer time to exucates..near about 2500 min??

Confirm?

[Fabio Pulcini]

no i don't need to pause the code.

I must create an array containing a time sequence that starts at midnight (00.00) of a not specified day and ends at 23.59 of that day. So that i can see each time minute by minute.

Answer 1

[madhan ravi]

DataArray.Format='H:mm'

[Fabio Pulcini]

thank you so much! i was using the wrong syntaxis

Answer 2

[KSSV]

t = 00.00:0.01: 23.59 ;

[KALYAN ACHARJYA]

@Time sir?

I dont undestand the logic of the question, Is he asking this one?

for i=2:iter  %iter value so that last cell element reached 23.59
    a{i}=a{i-1}+0.01;
    pause(n);  % Pause sec n
end
a=a';

[Fabio Pulcini]

Thanks for the answer, but it generates an array containing values with 2 decimals till .99.

I need a time array, minute by minute from midnight to 23.59 h.

[KSSV]

t0= hours(00.00) ;
t1 = hours(23.59) ;
t = t0:hours(0.01):t1

[madhan ravi]

it's a duration array not a time array

[KSSV]

So what? I gave two options..let the user decide what he wants....nothing is going to harm with that.

Answer 3

[Steven Lord]

minutesAfterMidnight = minutes(0):minutes(1):(hours(24)-minutes(1));
minutesAfterMidnight.Format = 'hh:mm';
firstTen = minutesAfterMidnight(1:10)
lastTen = minutesAfterMidnight(end-9:end)

You can add this to a datetime when or if you need times during a day.

minutesOfToday = datetime('today')+minutesAfterMidnight;
twoThirtyNineAM = minutesOfToday(2*60+40)

I added 40 instead of 39 when extracting 2:39 AM from minutesOfToday because 00:00 is element 1 of minutesAfterMidnight. Don't get caught by an off by one error.