summation using syms and rounding

is this way correct?Also want the number rounded to the first dp.

syms k
f = k-4/k-5;
v1 = subs(f, k, 1:3)
s_sum = sum(v1)
v2=subs(f,k,6:100)
s_sum2=sum(v2)
f=(0-4)/(0-5)
sum=s_sum+s_sum2+f
value = round(sum * 10) / 10

[Walter Roberson]

No, that is a product symbol, not a summation symbol.

Also, k-4/k-5 is parsed as (k-(4/k))-5

[dulanga]

okay thanks alot so how do i go about it ?

this is what i thought but the zero gives an error.

clc
clear
syms k
P1 = symprod((k-(4/k))-5 , k, 0, 3)
P2 = symprod((k-(4/k))-5 , k, 6, 100)

[Walter Roberson]

(k-4)/(k-5)

[dulanga]

The solution i get for this is wrong any idea why?

clc

clear

syms k

P1 = symprod((k-4)/(k-5) , k, 0,3)

P2 = symprod((k-4)/(k-5) , k, 6, 100)

sum= P1+P2

[Torsten]

Because you have to multiply P1 and P2, not add them.

[dulanga]

noted