How to caculate a value for a step - the previous step

So, I have a value x and i want a piece of code which would allow me to take x_current - x_one_step_previously for example at iteration 50 i would want x_50-x_49 is there a way to do this in Matlab. Thanks in advance to anyone who helps!!

Answer 1

[M]

It depends on what you mean by "I have a value x".

It is actuallyquite easy to do for a straightforward example, but it depends on your applications.

Could you provide more details about what you are trying to do ?

Otherwise here is an example:

x = zeros(1,50);
for i = 1 :50;
    x = i;
end
a = x (50) - x(49)

[Nikolaos Zafirakis]

So my x value is a vector 1x3 and i need to do (x_current-x_one_step_previous)/time

say the time=100 seconds.

[M]

x is a vector 1x3, you can still save its value in another vector, let's call is x_saved, a vector of dimension 3 x 100.

Would something like the following example work ?

x_saved = zeros(3,100);
for i = 1 : 100
    x = ... ; vector 1 x 3
    x_saved(:,i) = x;
    if i ~= 1
        delta = x(:,i)-x(:,i-1);
    end
end

Answer 2

[Steven Lord]

If you have numbered variables (which you shouldn't) then it will be painful.

If you have elements in an array, it's easy.

x = (1:20).'.^2;
dx = diff(x);

Note that dx has one fewer element than x, so if you want to display them together you'll need to augment it with an extra element like so:

dx2 = [0; dx];
t = table(x, dx2, 'VariableNames', {'x', 'delta_x'})

[Nikolaos Zafirakis]

Hello Steven,

I think you have misunderstood my question, hope this example clears it up. I look forward to your response.

kind regards,

Nikolaos

for i = 0:t

x(i) = (x1(i) - x2 /t1(i) -t2); % x2 and t2 are the state at the previous interval

end % so if at t = 20 i will have x(i) = (x1(20) - x2(19) /t1(20) -t2(19))