How to store values matrix in cell
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Hello,
I have an array as follows:
t= [ 1 2 3 ];
A matrix as follows:
M = [t^2 t 1 0 0 0;
0 0 0 t^2 t 1];
Now I want to store the process the M for 3 values of t i.e in this case [1 2 3].How do I do it.
like if t=1
then M=[1^2 1 1 0 0 0;0 0 0 1^2 1 1];
if t=2
then M=[2^2 2 1 0 0 0;0 0 0 2^2 2 1]; and so on.
Accepted Answer
More Answers (1)
KSSV
on 13 May 2019
M = @(t) [t^2 t 1 0 0 0;
0 0 0 t^2 t 1];
t = [1 2 3] ;
iwant = zeros(2,6,length(t)) ;
for i = 1:length(t)
iwant(:,:,i) = M(t(i)) ;
end
5 Comments
Tipu Sultan
on 13 May 2019
KSSV
on 13 May 2019
It will work...how you have used it? show us the full code.
Tipu Sultan
on 13 May 2019
KSSV
on 13 May 2019
clc; clear all ;
S = [100 0 0 0 0 0;
0 100 0 0 0 0;
0 0 100 0 0 0;
0 0 0 100 0 0;
0 0 0 0 100 0;
0 0 0 0 0 100];
prev_S = S;
Big_lambda = eye(2);
a=0;
b=0;
c=0;
p=0;
q=0;
s=0;
est_vec=[ a ; b; c; p; q; s];
theta = [ 45 46 48] ;
t= [ 1 2 3 ];
r= [200 210 220];
%Wanted = num2cell(M,1)
%[r,b,distance,angle]=deal(Wanted{:})
x = [ r; theta ; t];
%dif_x=zeros(2,3);
M = @(t) [t^2 t 1 0 0 0;
0 0 0 t^2 t 1];
t = [1 2 3] ;
iwant = zeros(2,6,length(t)) ;
for i = 1:length(t)
iwant(:,:,i) = M(t(i)) ;
end
time=4;
for i=1:3
M = iwant(:,:,i) ;
dif_x = [(-cos(theta(i))) (r(i).*sin(theta(i))) (2*a.*t(i)+b);(-sin(theta(i))) (-r(i).*cos(theta(i))) (2*p.*t(i)+q)]
W = dif_x(i)*Big_lambda(i)*dif_x(i)'
pred_x = x+randn(3)
y = M * est_vec + dif_x * (x(:,i)-pred_x(:,i))
K = prev_S*M'/((W + M*prev_S*M'))
%S =prev_S;
est_vec_new = est_vec + K*(y-M*est_vec)
cond = abs(est_vec_new - est_vec)
if cond < 0.003
break
end
est_vec = est_vec_new
a=est_vec(1,1)
b=est_vec(2,1)
c=est_vec(3,1)
p=est_vec(4,1)
q=est_vec(5,1)
s=est_vec(6,1)
S_new = (eye(6) - K*M)*S
S = S_new
r_cosTheta = a*time.^2+b*time+c % To calculate x co-ordinate for t>=3
r_sineTheta = p*time.^2+q*time+s % To calculate y co-ordinate for t>=3
%figure,plot(t,meas_equa1)
%new_t=[t,time];
%figure,plot(r_cosTheta,r_sineTheta)
end
%end
Tipu Sultan
on 13 May 2019
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