loop indexing length of non zeroes
    3 views (last 30 days)
  
       Show older comments
    
Hi, I'm trying to make a loop that finds the length of a sequence of numbers:
I want to find when x(:,4) is not equal to zero, and then find how long it's is the same number, I want to save the number and the start row, and the end row.
my output should look something like this: 
Id    start    end    length
10    1320    1331    11
9     1352    1354    3

thanks for any help    
3 Comments
Answers (2)
  Adam Danz
    
      
 on 3 Jun 2019
        
      Edited: Adam Danz
    
      
 on 4 Jun 2019
  
      Here are the steps needed to build your table. 
% Create fake data that looks like your example
x = rand(2000,5);
x(:,4) = 0;
x(1320:1331,4) = 10;
x(1352:1354,4) = 9;
% calculate table components
isZero = x(:,4)==0;
dz = [0;diff(isZero)];
start = find(dz == -1);         %start column 
endIdx = find(dz == 1)-1;       %end column
ID = x(start,4);                %ID column
len = endIdx - start;           %Length column
% Create table
T = table(ID,start,endIdx,len,'VariableNames', {'Id','start','endIdx','length'});
Result
T =
  2×4 table
    Id    start    endIdx    length
    __    _____    ______    ______
    10    1320      1331       11  
     9    1352      1354        2  
* Note that 'end' is not a valid variable name nor a valid table column name. 
0 Comments
  Steven Lord
    
      
 on 3 Jun 2019
        You can use the ischange function to identify abrupt changes in your data (the jump from 0 to 10 and the drop from 10 back down to 0.)
0 Comments
See Also
Categories
				Find more on Matrix Indexing in Help Center and File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!


