Is there a method to linear index to a transpose matrix without taking the transpose?
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Douglas Farinelli
on 18 Jun 2019
Commented: Douglas Farinelli
on 19 Jun 2019
Is there a method to linear index to a transpose matrix without taking the transpose?
5 Comments
Image Analyst
on 19 Jun 2019
What code is that? Where did you attach it? Who wrote it?
And what is wrong with using the transpose operator '? Why do you need a different way?
Accepted Answer
Douglas Farinelli
on 18 Jun 2019
2 Comments
Walter Roberson
on 18 Jun 2019
Yes.
Note: for a 2D matrix, ind2sub is (column_number - 1) * number_of_rows + row_number .
You can therefore optimize the access (row_number, column_number) to the transpose (column_number, row_number) as
(row_number - 1) * number_of_rows + column_number
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