can you write a vector function?

I am looking to express a parametrized vector function and draw the surface..

2 Comments

How can we help you with that? Where are you stuck?
What is the syntax for something like:
x(u,v) = ( 2-v*sin(u/2)*sin(u), 2-v*sin(u/2)*cos(u), v*cos(u/2) )
?

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 Accepted Answer

You pretty much wrote it yourself:
x = @(u,v) [2-v.*sin(u/2).*sin(u); 2-v.*sin(u/2).*cos(u); v.*cos(u/2)];
See the documentation sections on Anonymous Functions (link) and Vectorization (link) for an extended discussion of both. The documentation for the ndgrid (link) function will also be helpful.

4 Comments

can I create this function using the smbolic math toolbox?
You could, however that is going to be slower and less efficient than using the anonymous function implementation.
The Symbolic Math Toolbox is best for derivations and such that are done once, then using the matlabFunction function, implemented iin base MATLAB, taking advantage of its computational efficiencies.
Symbolic math is intriging.....efficiency is not an issue.
After looking at anonymous functions, I fail to see why you couldn't just define a function without the @ operator. Can you provided some insigh as to why this is necessary?
The @ operator denotes a function handle, and is necessary if you want to define it as an anonymous function. You could define it as a function file, however that is usually reserved for more complicated functions. See Function Basics for details.
You don’t have to define it as a function if you don’t want to — it will simply execute as a statement instead, although you could not then use it as a function later in your code — however in your original Question you specified that it is a function. See What Is a Function Handle? for an extended discussion.

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More Answers (1)

Ali Zain
Ali Zain on 6 Jan 2020
y= function(t)=[0.2582;
-0.3631 cos(0.21910*(t);
0.3572 cos(0.4158)(t);
0.3473*cos(0.6180t);
0.3336*cos(0.8135t);
0.3162*cos(t);
0.2954*cos(1.1756t);
0.2714*cos(1.3383t);
0.2443*cos(1.4863t);
0.2146*cos(1.6180t);
0.1826*cos(1.7321t);
0.1485*cos(1.8271t);
0.1128*cos(1.902t);
-0.0759*cos(1.9563t);
0.0382*cos(1.9890t)]
why it is giving error...

1 Comment

Except for the second line, there is no multiplication operator.

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