Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 2-by-1. Error in linear2d (line 7) z(:,1)=[0;1];

close all;

dt = 0.1;%time step

u1=1;

u2=1;

c = u2-u1;

u = sign(u2-u1);

z(:,1)=[0,1];

k=0.12;

m=2.21;%initial parameters

v=1;

a=1.4;

tend=1000;

t=0;

i=1

while t < tend-2*dt

vh=v(i)-dt*k*z(1,i)/ (2*m);

z(2,i) = z(1,i)+ dt*vh;

%a(i+1)= -k*z(i)/2;

v(i+1)= vh-dt*k*z(2,i)/ (2*m);% + dt*a(i+1)/2;

i = i+1;

t = t + dt

end

plot(z);

Answer 1

[KALYAN ACHARJYA]

You defined v=1, as scalar, but you called the function as vector v(i)

vh=v(i)-dt*k*z(1,i)/ (2*m);
%....^.........

When i=1, then v(1)=??

When i=2, then v(2)=?? in iterations.

Also the while loops runs multiple times

As t < tend-2*dt, where t=0 and tend=1000, dt=0.1, On such case the size of z also not sufficient

vh=v(i)-dt*k*z(1,i)/ (2*m);
%...............^......... 

Because z(:,1)=[0,1] allows only two iterations.

Requested to read about array indexing.

[Advait Sinha]

I am still getting the same error

[KALYAN ACHARJYA]

Yes, I have hinted where the error is, I have no idea what you doing inside the code. You have to properly define the v and z or you have to change the code. Please try to undestand why you getting the error? Probably you may solve it afterwards.

Answer 2

[Advait Sinha]

I am new to matlab so I’m finding it confusing and hard