obtaining the average value for a data set

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FATEMEH
FATEMEH on 4 Sep 2012
Hello, I have a data set which contains a value for a number of stations during some years (station, date, value). Data for some days is missing. I need to create a column with annual average value per station. I appreciate your help.
station date value average(yearly per station)
1 2001/1/1 2 2
1 2001/1/3 1 2
1 2001/1/5 3 2
2 2001/1/1 2 2.5
2 2001/1/4 3 2.5
1 2002/1/2 2 1.5
1 2002/1/6 1 1.5
2 2002/1/1 2 2.5
2 2002/1/2 3 2.5 . .
  3 Comments
Azzi Abdelmalek
Azzi Abdelmalek on 4 Sep 2012
Edited: Azzi Abdelmalek on 4 Sep 2012
can you specify the size of your data array, cell or .., how should the result looks like?
FATEMEH
FATEMEH on 4 Sep 2012
sorry for the misspecification. The last column is the column that should be created(average). My data has the form of matrix. I have 3 columns for year month and day. To be precise, a typical row has the form of: ( I separated the elements by *)
station* year* month* day*value
1 * 2001 * 1 * 1 * 2
and I want to add a column with yearly average per station:
station* year* month* day*value* average(yearly per station)
1 * 2001 * 1 * 1 * 2 *2

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Answers (1)

Matt Tearle
Matt Tearle on 4 Sep 2012
Edited: Matt Tearle on 4 Sep 2012
It looks like the fourth column is what you want to calculate. If so, this will do the job, assuming that you have the first three columns as station, date, and value (numeric vectors except date which is a cell array of strings)
% get the years from the date strings
dv = datevec(date);
year = dv(:,1);
% get all combinations of station & year
[stlist,yrlist] = meshgrid(unique(station),unique(year));
% allocate space for the calculated average
avg = zeros(size(station));
% loop over every station/year combination
for k = 1:numel(stlist)
% find the location of this combination in the data set
idx = (year == yrlist(k)) & (station == stlist(k));
% calculate the mean
avg(idx) = mean(value(idx));
end
This could probably be simplified with prior knowledge of the station numbers and years.
EDIT TO ADD: Given your comment above, ignore the first couple of lines -- you already have year.
  3 Comments
Sean de Wolski
Sean de Wolski on 6 Sep 2012
Why would you want to avoid the loop? The loop will likely be very fast and is easy to read/understand.
Matt Tearle
Matt Tearle on 6 Sep 2012
Possibly, although I doubt it will be neat. More importantly, why do you want to avoid loops?

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