MATLAB Answers

Rengin
0

Combination of sub-matrices generated within a for loop

Asked by Rengin
on 13 Aug 2019
Latest activity Commented on by Bruno Luong
on 13 Aug 2019
clear;
clc;
close all;
n=[3 1 2];
rad=[0.04 0.02 0.01];
h=[10 12 15];
for kk=1:length(n)
matrix=zeros(n(kk),n(kk));
for ii=1:n(kk)
for jj=1:n(kk)
val=rad(kk)*h(kk);
matrix(ii,jj)=val;
end
end
end
% Dear users, if you put a debug at the very last "end" (row 17), you can
% see that I aim to generate 3 sub-matrices having the size of 3x3, 1x1 and
% 2x2 (see n=[3 1 2]). I want to combine each sub-matrix one each other diagonally.
% I want to get the matrix as a result below:
matrix=[0.4 0.4 0.4 0 0 0;0.4 0.4 0.4 0 0 0;0.4 0.4 0.4 0 0 0;0 0 0 0.24 0 0;0 0 0 0 0.15 0.15;0 0 0 0 0.15 0.15];
%Is there any simple way to do it?
%Thanks in advance!

  3 Comments

Using the previous solution of your question gives the same result, please describe the situation where that condition contradicts your needs.
"The calculation of Val is different."
You might try to learn deeper how computer programming actually works, if you get stuck everytime the values change then you miss the whole purpose of programming.

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1 Answer

Answer by infinity
on 13 Aug 2019
 Accepted Answer

Hello,
There are various solutions for this question, one of the closet one to your current code could be
clear;
clc;
close all;
n=[3 1 2];
rad=[0.04 0.02 0.01];
h=[10 12 15];
matrix = zeros(sum(n));
for kk=1:length(n)
% matrix=zeros(n(kk),n(kk));
for ii=1:n(kk)
for jj=1:n(kk)
val=rad(kk)*h(kk);
matrix(ii+sum(n(1:kk-1)),jj+sum(n(1:kk-1)))=val;
end
end
end

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