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To generate alternate 0's and 1's

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brijesh soni
brijesh soni on 14 Aug 2019
Edited: Jos (10584) on 16 Aug 2019
Say I have A=[2 4 3 4 100 253 77 10 45]. I want to generate alternate 0's and 1' such that we have 2 zeros (i.e, zeros equal to size of 1st element), then 4 ones (ones equal to the size of 2nd element) and so on
Result should be : [0 0 1 1 1 1 0 0 0 1 1 1 1 . . . .]. How to do this?
  1 Comment
Rik
Rik on 14 Aug 2019
I'm guessing RunLength should help out.

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Accepted Answer

Andrei Bobrov
Andrei Bobrov on 14 Aug 2019
out = repelem(mod(0:numel(A)-1,2),A);

More Answers (2)

dpb
dpb on 14 Aug 2019
One brute force way--
B=[];
for i=1:numel(A)
B=[B (1-mod(i,2))*ones(1,A(i))];
end

Jos (10584)
Jos (10584) on 14 Aug 2019
Edited: Jos (10584) on 16 Aug 2019
bitget(repelem(0:numel(A)-1, A), 1)
[update] I modified my original but erroneous answer bitget(repelem(1:numel(A), A), 2). In his comments below, Andrei hit a serious flaw in this one. One does need to look at the last bit!
Thanks Andrei, for pointing this out.
  4 Comments
Jos (10584)
Jos (10584) on 16 Aug 2019
Sorry! You're complete right to look only at the last bit!

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