How to find eigenvalues for a system of lenearized ordinary differential equations?
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I have a system of linearized ODEs with corresponding boundary conditions.
%----------------------------system of ODEs--------------------------------------%
y'(1)=y(2)
y'(2)=y(3)
y'(3)=(phi./Da).*y(2)+(2.*phi.*Fr./A1).*fd.*y(2)-(fd1.*1./A1).*y(3)-(fdd.*1./A1).*y(1)+(2.*fd.*1./A1).*y(2)-(e./A1).*y(2)-(phi.*Ra./(A1^2).*A2).*y(4)
y'(4)=y(5)
y'(5)=-(Pr./A2).*(fd.*y(5)+thd.*y(1)+e.*y(4))];
%---------------------------boundary conditions----------------------------------%
y(1)=y(2)=y(4)=0 at eta=0
y(2)=y(4)=0 at eta=0;
here Pr phi Ra Da Fr A1 A2 fd1 fd fdd thd are known quantities and 'e' is unknown.
I need to solve the system to find out the eigenvalues (e).
Thanks in advance.
Accepted Answer
More Answers (2)
Pavel Osipov
on 9 Oct 2019
0 votes
Hi!
det(p*E-A)=0. This is the equation for the eigenvalues of p. - -> The unkown "p" is solution det(p*E-A)=0. det - is the determinant with dimensions 5x5.
px-Ax=0 ->Ax=px, p is eigenvalues of A MATLAB command [V,D] = eig(A) returns diagonal matrix D of eigenvalues and matrix V whose columns are the corresponding right eigenvectors, so that A*V = V*D. (from MATLAB help).
eigenvalues p is 5x1 vector = liagonal elements D. eigenvectors of A see at columns V.
1 Comment
Tanya Sharma
on 21 Oct 2019
Pavel Osipov
on 24 Nov 2019
0 votes


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