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Finding average step size and slope with ode45

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EB
EB on 9 Oct 2019
Commented: Star Strider on 12 Oct 2019
I want to be able to calculate the average step size and slope for each value in the loop.
I first want to plot the log values of dT and TOL.
I believe my average step size (dT) should be the average of 1/T.
t = [0, 5]; % time span
y0 = 1; % initial condition
dy0 = 2; % initial condition first derivative
dydt = @(t,y) [y(2); ((1 - y(1)^2))*y(2) - y(1)];
for j = 1:10
TOL(j) = 1*exp(-1-j);
options = odeset('AbsTol',TOL(j),'RelTol',TOL(j));
[T{j},Y{j}] = ode45(dydt, t, [y0, dy0], options);
dT = mean(1/length(T)); % average step size
plot(log(dT),log(TOL));
hold on;
grid
j = j+1;
end
hold off;
Errors I'm facing:
  • my plot doesn't show up
  • my slope receives the error 'Undefined function 'log' for input arguments of type 'cell'.'
  • not sure if I am thinking of average step size correctly
Side note: Would I be able to generate multiple slopes using polyfit in one graph?

Accepted Answer

Star Strider
Star Strider on 9 Oct 2019
Subscript ‘dT’ as well. The code will be more efficient if you move the plot outside the loop:
t = [0, 5]; % time span
y0 = 1; % initial condition
dy0 = 2; % initial condition first derivative
dydt = @(t,y) [y(2); ((1 - y(1)^2))*y(2) - y(1)];
for j = 1:10
TOL(j) = 1*exp(-1-j);
options = odeset('AbsTol',TOL(j),'RelTol',TOL(j));
[T{j},Y{j}] = ode45(dydt, t, [y0, dy0], options);
dT(j) = mean(1/length(T)); % average step size
end
figure
plot(log(dT),log(TOL));
grid
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