Duplicate Each Element in a Matrix without using Repelem or Repmat
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Is there a way I can make each element in a matrix duplicate into a 3 by 3? if
A=[1 0;0 1]
Is there a way i can turn it into
Aew=[1 1 1 0 0 0;1 1 1 0 0 0;1 1 1 0 0 0;0 0 0 1 1 1;0 0 0 1 1 1;0 0 0 1 1 1]
so basically
Anew=repelem(A,3,3)
but without repelem, repmat or any special functions?
Thanks
1 Comment
Adam
on 31 Oct 2019
Yes, but the only reason I can see for wanting to do so is as a homework question. Like most things you can do it with a for loop.
Accepted Answer
More Answers (1)
>> A = [1,0;0,1]
A =
1 0
0 1
>> V = ceil((1:6)/3);
>> B = A(V,V)
B =
1 1 1 0 0 0
1 1 1 0 0 0
1 1 1 0 0 0
0 0 0 1 1 1
0 0 0 1 1 1
0 0 0 1 1 1
5 Comments
Benjamin Ong
on 1 Nov 2019
"This way only seems to produce a 2 by 2 everytime though no matter the size of the initial matrix"
Clearly it works, as the example in my answer shows.
Of course it can be trivially adjusted to replicate the elements of any sized array any number of times, to do so requires two very small changes to the V definition:
k = 3;
V = ceil((1:k*size(A,1))/k);
This is certainly a much simpler and more efficient solution than the one that you accepted.
Benjamin Ong
on 2 Nov 2019
Ayca Yigit
on 4 May 2021
How does it work?
Stephen23
on 4 May 2021
@Ayca Yigit: it generates a vector of indices V, where each index repeats k times. Consider what happens when you use those indices to select the elements of A(V,V).
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