Finding transpose of values.

ts = xlsread('ArrowHead_TRAIN.xlsx');
for i = 1:100
    b=20
     p=ts(i,:);
    n= numel(p);
     Z=mat2cell(p,diff([0:b:n-1,n]));
    A=transpose(Z);
celldisp(A)
end

I want to find the transpose of Z values.I need the elements of Z in an array order.I used transpose,but not working.How can I get the elements of Z in an array form.Please help me.

Answer 1

[Walter Roberson]

ts = xlsread('ArrowHead_TRAIN.xlsx');
for i = 1 : size(ts,1)
    b = 20;
    p = ts(i,:);
    n = numel(p);
    Z = mat2cell(p, 1, diff([0:b:n-1,n]));
    A = cellfun(@transpose, Z, 'uniform', 0);
    celldisp(A)
end

[Silpa K]

Thank you sir. How can I get result in row wise.I need a result in row wise.

[Walter Roberson]

The result is row-wise if you do not do the transpose.