MATLAB Answers

Too many output arguments.

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Paul Rogers
Paul Rogers on 16 Dec 2019
Edited: per isakson on 18 Dec 2019
I've found this code that may help me a lot.
I cannot run, it keeps saying:
Error using type
Too many output arguments.
my version is 2014b
the code is
function [t,y]=valori(type)
a=340;
S=0.25;
x10=0.85;
U=144;
if (type == 1)
Ac=0.0034;
Vp=0.32;
Lc=0.3;
H=3.2613e4;
W=0.3689;
else
if (type == 2)
Ac=0.0033;
Vp=0.025;
Lc=1.22;
H=0.09e5;
W=0.1;
else
Ac=0.0090;
Vp=0.001;
Lc=2.8;
H=1.55e4;
W=0.1587;
end
end
[t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S);
end
function [t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S)
wh=a*sqrt(Ac/(Vp*Lc));
B=U/(2*wh*Lc);
k=x10-S*(x10-(1/3)*(x10.^3));
[t,y]=ode45(@(t,y)greitzer10(H,W,B,U,Ac,y,S,k),[0 100],[0,0]);
subplot(2,2,1)
plot(t,y(:,1))
xlabel('t')
ylabel('\phi_c')
subplot(2,2,2)
plot(y(:,1),y(:,2))
xlabel('\phi_c')
ylabel('\psi')
subplot(2,2,3)
plot(t,y(:,2))
xlabel('t')
ylabel('\psi')
end
function dydt = greitzer10(H,W,B,U,Ac,y,S,k)
dydt = [ ((3*H*Ac*B)/(W*U))*((y(1)-(1/3)*((y(1).^3)))-y(2)); ((W*U)/(3*H*Ac*B))*(y(1)-(S*y(2)+k)) ];
end
this might be a missing part:
function y=carcomp(C0,H,x,W)
y=C0+H*(1+(3/2)*((x/W)-1)-(1/2)*(((x/W)-1).^3));

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Accepted Answer

per isakson
per isakson on 17 Dec 2019
Edited: per isakson on 17 Dec 2019
I fail to reproduce the error you report
>> [t,y] = valori( 2 );
>> [t,y] = valori( 1 );
>> [t,y] = valori( 3 );
no error, no warning and produces a figure with three diagrams.
However
>> [t,y] = valori( type );
Error using type
Too many output arguments.
>>
"type" is the name of a function that doesn't return any output. Try
>> type=1; [t,y] = valori( type );
That works, but now you'll get unexpexted results if you try to use the function, type
Conclusion: Avoid to use function names as names of variables.

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per isakson
per isakson on 17 Dec 2019
Add
%
C0 = 0; % or a better value
cc = carcomp( C0, H, t, W );
subplot(2,2,4)
plot( t, cc )
xlabel('t')
ylabel('carcomp')
at the end of the function, valori. That fills the "missing quadrant", but maybe not with the data you expected.
Paul Rogers
Paul Rogers on 17 Dec 2019
function [t,y]=valori(type)
a=340;
S=0.25;
x10=0.85;
U=144;
if (type == 1)
Ac=0.0034;
Vp=0.32;
Lc=0.3;
H=3.2613e4;
W=0.3689;
else
if (type == 2)
Ac=0.0033;
Vp=0.025;
Lc=1.22;
H=0.09e5;
W=0.1;
else
Ac=0.0090;
Vp=0.001;
Lc=2.8;
H=1.55e4;
W=0.1587;
end
end
[t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S);
end
function [t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S)
wh=a*sqrt(Ac/(Vp*Lc));
B=U/(2*wh*Lc);
k=x10-S*(x10-(1/3)*(x10.^3));
[t,y]=ode45(@(t,y)greitzer10(H,W,B,U,Ac,y,S,k),[0 100],[0,0]);
subplot(2,2,1)
plot(t,y(:,1))
xlabel('t')
ylabel('\phi_c')
subplot(2,2,2)
plot(y(:,1),y(:,2))
xlabel('\phi_c')
ylabel('\psi')
subplot(2,2,3)
plot(t,y(:,2))
xlabel('t')
ylabel('\psi')
end
function dydt = greitzer10(H,W,B,U,Ac,y,S,k)
dydt = [ ((3*H*Ac*B)/(W*U))*((y(1)-(1/3)*((y(1).^3)))-y(2)); ((W*U)/(3*H*Ac*B))*(y(1)-(S*y(2)+k)) ];
end
function y=carcomp(C0,H,x,W)
y=C0+H*(1+(3/2)*((x/W)-1)-(1/2)*(((x/W)-1).^3));
end
C0 = 0; % or a better value
cc = carcomp( C0, H, t, W );
subplot(2,2,4)
plot( t, cc )
xlabel('t')
ylabel('carcomp')
then i type in the command
type=1; [t,y] = valori( type );
but it says this:
Error: File: valori.m Line: 63 Column: 1
This statement is not inside any function.
(It follows the END that terminates the definition of the function "carcomp".)
per isakson
per isakson on 18 Dec 2019
"This statement is not inside any function." Why did you put it at the end of the file?
Read up on function and Local Functions
Here is a screen clip of the end of your file valori.m
Comments
  • Upper left corner. With an indention of 4, I find it easier to see the scope of the functions.
  • Upper right corner. The red box shows that the Code Analyzer has spotted a syntax error. Try to understand and fix that problem before running the code. See Check Code with the Code Analyzer
  • The arrow points at the the end of the function valori.
Move the lines 61-66 to the end of the function valori.

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