Why is my circle invisible?

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Jenny Andersen
Jenny Andersen on 18 Dec 2019
Commented: Walter Roberson on 18 Dec 2019
I can not figure out why my circle is invisiable when I plot it (It is a regression). Am I missing something? It used to work earlier.
x = [5; 4; -1; 1];
y = [3; 5; 2; 1];
% circle's equation: x^2+y^2 = 2xc1+2yc2+c3
a = [2.*x,2.*y,ones(length(x),1)];
b = [x.^2 + y.^2];
c = a\b;
x_m = c(1)/2;
y_m = c(2)/2;
r = sqrt(x_m^2 + y_m^2 -c(3));
% plot data points
plot(x,y,'o')
hold on
% plot center
plot(x_m,y_m,'+')
% plot circle
circle(x_m,y_m,r)
hold off
  2 Comments
KSSV
KSSV on 18 Dec 2019
For that we should have a look on the function circle.
Jenny Andersen
Jenny Andersen on 18 Dec 2019
It is no function, only an expression.

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Accepted Answer

Walter Roberson
Walter Roberson on 18 Dec 2019
Edited: Walter Roberson on 18 Dec 2019
viscircles([x_m, y_m], r)
axis equal
  7 Comments
Walter Roberson
Walter Roberson on 18 Dec 2019
Which MATLAB release are you using, and do you have the Image Processing Toolbox (that defines viscircles())
Walter Roberson
Walter Roberson on 18 Dec 2019
There are File Exchange contributions to draw circles, including https://www.mathworks.com/matlabcentral/fileexchange/59244-circles

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