Creating an array from 1 to n

2,469 views (last 30 days)
Hello!
I am trying to create an array of integers from 1 to n [1 2 3 ..... n], where n is a variable that can change.
How should I approach that?
Thank you!
  3 Comments
Stephen
Stephen on 27 Jul 2021
@Luis Benitez Prieto: like this:
V = uint32(1):uint32(10)
V = 1×10
1 2 3 4 5 6 7 8 9 10
class(V)
ans = 'uint32'
Note that just one uint32 input is sufficient to define the output as uint32:
class(uint32(1):10)
ans = 'uint32'
class(1:uint32(10))
ans = 'uint32'
Note that the square brackets in your example are superfluous and misleading:

Sign in to comment.

Accepted Answer

Alex Mcaulley
Alex Mcaulley on 20 Dec 2019
n = 10 %
1:n
ans =
1 2 3 4 5 6 7 8 9 10
  2 Comments

Sign in to comment.

More Answers (1)

Suraj Sudheer Menon
Suraj Sudheer Menon on 26 Jun 2020
Edited: madhan ravi on 26 Jun 2020
B=sort(A);
for i=2:numel(B)
if(B(i)==B(i-1)
B(i)=false;
end
end
B(B==false)=[];
A(A==B)=[]
  1 Comment
madhan ravi
madhan ravi on 26 Jun 2020
How’s this related to this thread?

Sign in to comment.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!