I need only words when i split a string , while currently i am getting even spaces

string2=split(string(result{1,hh}(ss,1)),[" ",",","(",")","-"])

>> string2
string2 = 
  8×1 string array
    "Secure"
    "VPDM"
    "to"
    "Ebay"
    "housing"
    ""
    "optional"
    ""

I need the output to be

    "Secure"
    "VPDM"
    "to"
    "Ebay"
    "housing"
    "optional"

Answer 1

[Guillaume]

Probably the easiest is to do:

string2 = regexp(yourstring, '\w+', 'match')

[Prajwal Venkatesh]

I can sometimes have numbers in there too

What should i do then?

[Walter Roberson]

Caution: \w will not match ' or - characters or period.

Don't pay $29.95 for e-mail!

Would get broken into

Don
t
pay
29
95
for
e
mail

It can be difficult to define what "words" are in English.

[Prajwal Venkatesh]

also i want the output to be strings

[Walter Roberson]

string() the cell array that regexp returns.

[Walter Roberson]

\w already includes the digits. It would not include decimal points or commas or positive or negative signs or scientific notation. If you need to include numbers it is best to define exactly which numeric formats you will support.

Floating point numbers are always a nuisance to write expressions for, especially if you permit leading 0 to be omitted such as .716e-3 instead of 0.716e-3

[Prajwal Venkatesh]

>> (regexp(string2, '\w+', 'match'))

ans =

8×1 cell array

{["Secure" ]}

{["VPDM" ]}

{["to" ]}

{["Ebay" ]}

{["housing" ]}

{0×0 string }

{["optional"]}

{0×0 string }

Error using string

Conversion from cell failed. Element 6 must be

convertible to a string scalar.

This is the issue

[Image Analyst]

Can you attach your string2 and/or result in a .mat file so we can use it?

save('answers.mat', 'string2', 'result');

[Walter Roberson]

Is string2 a string scalar or a non-scalar string array?

[Prajwal Venkatesh]

I am attaching answers.mat

[Walter Roberson]

string2 comes out as missing in that file, and there is no way that that result variable is the output of that regexp() command.