# Iterating through 2 Arrays and Performing a Calculation

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Graduate Student on 6 Mar 2020
Answered: Sindar on 6 Mar 2020
A1 = [5 10 15 20 25 30 35 40]
A2 = [ 7 22 38]
Goal: Iterate through A2 and subtract from appropriate value in A1, store this value in a separate array.
Example:
7 in A2 is between 10 and 5 where
t1= 5
t2 = 10
Subtract A2 from t1.
7-5 = 2 (store this value in a separte array.
Move on to the second element in A2, 22. 22 is between 20 and 25. Substract (22-20) = 2; store this value

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Graduate Student on 6 Mar 2020
A2 is not evenly space but it sorted. The next value is always bigger than the previous.
I'm not sure what you mean by third question. A2 will aways be larger than T1. So when you subtract, it will always be a positive integer.
Sindar on 6 Mar 2020
Ah, sorry, I asked the wrong question: Will A2 ever have elements less than all the elements in A1? (so t1 doesn't exist). Also, how many elements, roughly, will A1 and A2 have?
Graduate Student on 6 Mar 2020
There are about ~1000 elements in each array although each array is a different length from each other. No, A2 will not be less than A1. Thanks!

Sindar on 6 Mar 2020
loop version:
for ind=1:length(A2)
idx = find(A1 < A2(ind),1,'last');
A3(ind) = A2(ind) - A1(idx);
end
Another (probably much worse) way of looking at it for smallish arrays:
A1 = [3 10 15 20 25 30 35 40];
A2 = [ 7 22 38];
% create a matrix of all combinations of A1(i)-A2(j)
tmp = A2-A1';
% set any less than zero to infinity
tmp(tmp<0)=Inf;
% find the minimum for each column
A3 = min(tmp)