# Error using varfun function. "Matrix dimensions must agree."

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NATALIA ARREGUI GONZALEZ
on 19 Mar 2020

Commented: NATALIA ARREGUI GONZALEZ
on 20 Mar 2020

Hello guys,

I am trying to do the following operation:

I want to multiply a table of 52824x9, named X, by the first column of a table of 9x4. The table's name is coef, the first column variable name is Estimate. Therefore I would like to do something like this:

yPred=X*coef.Estimate

I am using the varfun function in the following way:

yPred=varfun(@(x) x.*coef.Estimate,X);

However, I am getting the following message:

Error using tabular/varfun>dfltErrHandler (line 433)

Applying the function '@(x)x.*coef.Estimate' to the variable 'VarName3' generated the following error:

Matrix dimensions must agree.

As I understand, I am multiplying 52824x9*9x1, so I don't know where my mistake is.

If anyone knows how to solve this, or could provide any solution it would be very much appreciated.

Many thanks,

Natalia

##### 2 Comments

the cyclist
on 19 Mar 2020

### Accepted Answer

Guillaume
on 19 Mar 2020

Several points:

- "As I understand, I am multiplying 52824x9*9x1" No, you're using .*, the memberwise multiplication, not * the matrix multiplication. With .* the matrices must have the same size in all dimensions unless or one of them must be scalar in the mismatched dimensions.
- "I want to multiply a table of 52824x9". Multiplication on tables are not defined. You could transform a table as long as all the variables are numeric matrices and multiply that but you cannot multiply tables. Typically tables contain heterogeneous data so multiplication wouldn't make sense.
- varfun applies the given function to each variable of the table in turn. So the x that your function receives will be 52824x1. I don't think you want to use varfun.
- The variables of your tables are day, month, period, holiday (which is just a 0/1 flag), etc. Does it even make sense to multiply variables like day or month, by your coeff variables?
- It looks like you're trying to do a linear fit. Can you even do a linear fit when one of your variable is a 0/1 flag?

##### 3 Comments

Guillaume
on 19 Mar 2020

data{:,:} * coeff{:,:}

or

table2array(data) * table2array(coeff)

would multiply the content of both tables.

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