Using fminbnd to find the max value.

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Jose Grimaldo
Jose Grimaldo on 15 Apr 2020
Edited: Walter Roberson on 15 Apr 2020
How can I find the max value between 0.5 - 5 using fminbnd?
m=.09
b=2.7
Eq1=@(x) b.*(x.^m)
% I try this but I get an error
Maxp=fminbnd(Eq1.*-1,0.5,5)

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Accepted Answer

Walter Roberson
Walter Roberson on 15 Apr 2020
Edited: Walter Roberson on 15 Apr 2020
[Bestx, Maxp] = fminbnd(@(x) -Eq1(x), 0.5, 5)

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