Sequential, row-wise reshape of an M–by–N matrix to form a 1–by–N vector

6 views (last 30 days)
Dumb question. Let's say I have the following matrix:
A = [2 1
4 3
6 5
8 7
10 9];
Is there a way to use circshift(), some combinaton of circshift(), reshape(), transpose(), etc, or other set of functions to obtain the following.
A = somefun(A) % or combinaton of functions and operations
A =
2 1 4 3 6 5 8 7 10 9
I could easily obtain this result with with a for loop, but I am wondering if there is another means to go about this. Notice that the rows are sequentially 'stacked' along the N–dimension. The question could similarly be phrased in terms of columns to produce an M–by–1 column vector.
Edit: Accidental, premature submit.

Accepted Answer

Stephen23
Stephen23 on 22 Apr 2020
reshape(A.',1,[])

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!