Symbolic integration using 'int': Find integration constant using symbolic initial condition

Hi, using 'syms' and 'int' I solve symbolic integral, which provides me the answer with integration constant 'C'. The result is a long-expression and I wish to define the initial condition, e.g., y(0)=a, so I can find the closed-form expression with the integration constant.

Is there a way to define symbolic initial conditions and get the complete solution?

best,

Answer 1

[Walter Roberson]

constant = a - subs(TheExpression,Variable,0) + C

For example, TheExpression(0) might be 5+C and a might be 2, and 2 - (5+C) + C = 2-5 = -3 which is the constant of integration