Filling a vector with ones based on a given value

HI all again,

I have one vector A and a matrix B:

Vector A has integers values from 0 to 6, A=[0 1 3 2 0 4 5 2 1 6]' (column vector, 10 values)

Matrix B has size 10 X 6, where in each row the element of A is split into ones, until the A(i) value is reached

for example B would be like that B=[0 0 0 0 0 0;1 0 0 0 0 0;1 1 1 0 0 0;....]

Is there any quick way to do it, avoiding multiple "if'?

thanks a lot,

Nikolas

Answer 1

[Ameer Hamza]

A = [0 1 3 2 0 4 5  2 1 6].';
M = repmat(1:6, numel(A), 1) <= A;

Result

>> M
M =
  10×6 logical array
   0   0   0   0   0   0
   1   0   0   0   0   0
   1   1   1   0   0   0
   1   1   0   0   0   0
   0   0   0   0   0   0
   1   1   1   1   0   0
   1   1   1   1   1   0
   1   1   0   0   0   0
   1   0   0   0   0   0
   1   1   1   1   1   1

It gives a logical matrix. To get a numeric matrix

M = M*1;

[Nikolas Spiliopoulos]

thanks a lot,

It's what I want, and it's much quicker than what I tried!

thanks!!

[Ameer Hamza]

I am glad to be of help.

Answer 2

[Matt J]

B=(A(:)>=1:6)