# how to reshape the matrix

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Shehab Tarek on 18 May 2020
Edited: Sai Bhargav Avula on 18 May 2020
i have matrix =001001001111011101111;
and i want to convert it to
001
001
001
111
011
101
111
i know reshape function
matrix=reshape(matrix,[],3);
but it not get the answer which i need

David Hill on 18 May 2020
m =[0 0 1 0 0 1 0 0 1 1 1 1 0 1 1 1 0 1 1 1 1];
a=reshape(m,3,[])';

Stephen Cobeldick on 18 May 2020
This answer works, I don't see what the problem is:
>> m = [0,0,1,0,0,1,0,0,1,1,1,1,0,1,1,1,0,1,1,1,1];
>> a = reshape(m,3,[]).'
a =
0 0 1
0 0 1
0 0 1
1 1 1
0 1 1
1 0 1
1 1 1
Shehab Tarek on 18 May 2020
good
but how to make the first line from double matrix to M=[0,0,1,......];
Stephen Cobeldick on 18 May 2020
M=[0,0,1,......];
is also a double matrix. Try it and see:
>> M=[0,0,1];
>> class(M)
ans = double
So instead of a double array you want a double array? In any case, reshape does not change the array type, so whatever type array you have at the start is what you will get at the end.

Sai Bhargav Avula on 18 May 2020
Edited: Sai Bhargav Avula on 18 May 2020
Hi,
Try the following code
convert matrix to char
matrix ='001001001111011101111';
matrix=reshape(matrix,[],3);
Hope this helps!

Stephen Cobeldick on 18 May 2020
"I understood that the input is..."
If the input is either:
• a character vector of '0' and '1' characters, or
• a numeric vector of 0 and 1 values,
then exactly the same operations (reshape and transpose) can be applied to get the requested order.
"I understood that the expected output to be 7*1 martix and not a 7*3 matrix"
This is certainly possible, but does not resolve that your code still put the wrong input elements in the wrong locations. Converting it to a 7x1 string array does not fix that.
>> matrix ='001001001111011101111';
matrix =
001
011
110
011
011
101
011
Lets compare your output against the requested output given in the original question:
your: original:
001 001
011 001
110 001
011 111
011 011
101 101
011 111
Converting to string will not fix that your code put the incorrect elements in each row.
Discussion of input class and output type conversion are simply distractions from that.
Shehab Tarek on 18 May 2020
Sai Bhargav Avula on 18 May 2020
Thanks for the explanation and clearing my confusion Stephen Cobeldick,
I was thinking more about matrix being a single value(matrix = 001001001111011101111) and not an array( [0 0 1 .....]) and output to be a single colum vector (7*1) and overlooked the expected result .
matrix ='001001001111011101111';
matrix= string(reshape(matrix,3,[])');