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i have matrix =001001001111011101111;

and i want to convert it to

001

001

001

111

011

101

111

i know reshape function

matrix=reshape(matrix,[],3);

but it not get the answer which i need

David Hill
on 18 May 2020

m =[0 0 1 0 0 1 0 0 1 1 1 1 0 1 1 1 0 1 1 1 1];

a=reshape(m,3,[])';

Stephen Cobeldick
on 18 May 2020

This answer works, I don't see what the problem is:

>> m = [0,0,1,0,0,1,0,0,1,1,1,1,0,1,1,1,0,1,1,1,1];

>> a = reshape(m,3,[]).'

a =

0 0 1

0 0 1

0 0 1

1 1 1

0 1 1

1 0 1

1 1 1

Stephen Cobeldick
on 18 May 2020

Your example:

M=[0,0,1,......];

is also a double matrix. Try it and see:

>> M=[0,0,1];

>> class(M)

ans = double

So instead of a double array you want a double array? In any case, reshape does not change the array type, so whatever type array you have at the start is what you will get at the end.

Sai Bhargav Avula
on 18 May 2020

Edited: Sai Bhargav Avula
on 18 May 2020

Hi,

Try the following code

convert matrix to char

matrix ='001001001111011101111';

matrix=reshape(matrix,[],3);

Hope this helps!

Stephen Cobeldick
on 18 May 2020

"I understood that the input is..."

If the input is either:

- a character vector of '0' and '1' characters, or
- a numeric vector of 0 and 1 values,

then exactly the same operations (reshape and transpose) can be applied to get the requested order.

"I understood that the expected output to be 7*1 martix and not a 7*3 matrix"

This is certainly possible, but does not resolve that your code still put the wrong input elements in the wrong locations. Converting it to a 7x1 string array does not fix that.

>> matrix ='001001001111011101111';

>> matrix=reshape(matrix,[],3) % your code

matrix =

001

011

110

011

011

101

011

Lets compare your output against the requested output given in the original question:

your: original:

001 001

011 001

110 001

011 111

011 011

101 101

011 111

Converting to string will not fix that your code put the incorrect elements in each row.

Discussion of input class and output type conversion are simply distractions from that.

Sai Bhargav Avula
on 18 May 2020

Thanks for the explanation and clearing my confusion Stephen Cobeldick,

I was thinking more about matrix being a single value(matrix = 001001001111011101111) and not an array( [0 0 1 .....]) and output to be a single colum vector (7*1) and overlooked the expected result .

The answer should have been like what David answered

matrix ='001001001111011101111';

matrix= string(reshape(matrix,3,[])');

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