isAlways: what did I do wrong?

2 views (last 30 days)
Art
Art on 6 Nov 2012
Hi,
I have a somewhat complicate function of only 1 variable. When I plot it from the range [1, 10], it's clear that the function is always negative. However, when I use isAlways (with appropriate assumptions on the domain of the function), it gives me an unknown (unable to prove). Please find the sample code below. Seems like you'd need R2012 for assumeAlso to work.
Thanks a lot!
clear;
syms x real
W2 = 2*((25*(3*x - 30))/(11*(25*x - 8)^2) - 3/(11*(25*x - 8)) + 75/(25*x - 8)^2)*((3*x - 30)/(11*(25*x - 8)) + 3/(25*x - 8) - 1/11) - 2*((25*(3*x - 27))/(11*(25*x + 17)^2) - 3/(11*(25*x + 17)))*((3*x - 27)/(11*(25*x + 17)) - 1/11);
assumeAlso(x >= 1);
assumeAlso(x < 10);
fW2 = inline(char(W2));
fplot(fW2, [1, 10]);
isAlways(W2 < 0, 'Unknown', 'error');
  1 Comment
Art
Art on 6 Nov 2012
Nevermind... got it, I think. After I did
W2 = simple(W2);
And do the same thing, it gives me the answer.
Thanks!

Sign in to comment.

Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!