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Implementation of a matrix

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Franzi
Franzi on 16 Jun 2020
Commented: madhan ravi on 18 Jun 2020
This question was flagged by James Tursa
Hello!

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madhan ravi
madhan ravi on 18 Jun 2020
Huh... why waste others time by asking a question if it’s going to be deleted anyway??

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Accepted Answer

James Tursa
James Tursa on 16 Jun 2020
You haven't told us what x and e are, but assuming x is a vector and e is a scalar, simply this:
result = cos( (1:n) .* x(:) * e )

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Steven Lord
Steven Lord on 16 Jun 2020
What is the value of n?
What are the sizes of each of a, x, and y?
What do you mean by "whats[sic] wrong"?
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  • Did MATLAB crash? If so please send the crash log file (with a description of what you were running or doing in MATLAB when the crash occured) to Technical Support using the telephone icon in the upper-right corner of this page so we can investigate.

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More Answers (2)

Vishal Gaur
Vishal Gaur on 16 Jun 2020
Code to generate the mentioned output is:
for i=x
for j=1:n
matCos(i,j) = cos(j*x(i)*exp(1));
end
end

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David Hill
David Hill on 16 Jun 2020
If x and e are symbolic
syms x1 x2 x3 x4 x5 x6 x7 x8 x9 x10 e;
x=[x1 x2 x3 x4 x5 x6 x7 x8 x9 x10];
for k=1:n
y(k,:)=cos((1:n)*k*x(k)*e);
end

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