# Implementation of a matrix

3 views (last 30 days)
Franzi on 16 Jun 2020
Commented: madhan ravi on 18 Jun 2020
This question was flagged by James Tursa
Hello!

#### 1 Comment

madhan ravi on 18 Jun 2020
Huh... why waste others time by asking a question if it’s going to be deleted anyway??

James Tursa on 16 Jun 2020
You haven't told us what x and e are, but assuming x is a vector and e is a scalar, simply this:
result = cos( (1:n) .* x(:) * e )

#### 1 Comment

Steven Lord on 16 Jun 2020
What is the value of n?
What are the sizes of each of a, x, and y?
What do you mean by "whats[sic] wrong"?
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Vishal Gaur on 16 Jun 2020
Code to generate the mentioned output is:
for i=x
for j=1:n
matCos(i,j) = cos(j*x(i)*exp(1));
end
end

David Hill on 16 Jun 2020
If x and e are symbolic
syms x1 x2 x3 x4 x5 x6 x7 x8 x9 x10 e;
x=[x1 x2 x3 x4 x5 x6 x7 x8 x9 x10];
for k=1:n
y(k,:)=cos((1:n)*k*x(k)*e);
end