What does "IND" do?
130 views (last 30 days)
Show older comments
Alice Marin
on 8 Jul 2020
Commented: Alice Marin
on 8 Jul 2020
Could someone please explain what is the meaning behind the following sequences? I don't quite understand the meaning of the "ind" function.
Thank you!
P.S. I don't know whether it is worth mentioning, but the code was written using Octave.
-------------------------
indBl=[];
%
if (Blt(1) == 1)
indBl=[indBl 1];
end
if (Blr(1) == 1)
indBl=[indBl 2];
end
%
if (Blt(2) == 1)
indBl=[indBl 2*NE1+1];
end
if (Blr(2) == 1)
indBl=[indBl 2*NE1+2];
end
%
if (Blt(3) == 1)
indBl=[indBl 2*NE+1];
end
if (Blr(3) == 1)
indBl=[indBl 2*NE+2];
end
0 Comments
Accepted Answer
Walter Roberson
on 8 Jul 2020
There is no "ind" function in that code.
What the code is doing is adding values to the end of a list.
If Blt(1) is 1, then add 1 to the end of the list.
Then if Blr(1) is 1, add 2 to the end of the list (that might have been updated in the previous step.)
Then if Blt(2) is 1, add 2*NE1+1 to the end of the list.
And so on.
The [] is the same as horzcat() for this purpose, so you could write it as
if Blt(1) == 1
indBl = horzcat(indBl, 1);
end
You could also write it as
if Blt(1) == 1
indBl(end+1) = 1;
end
More Answers (0)
See Also
Categories
Find more on Octave in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!