implementation of a matrix

1 view (last 30 days)
Hello! I want to implement the following matrix:
where is a given vector of random indices
Can someone help me to implement that?
  3 Comments
Franziska Bömann
Franziska Bömann on 19 Jul 2020
yes, I did, but I cannot understand how to implement matrices, thats why I'm always asking about matrices.
madhan ravi
madhan ravi on 19 Jul 2020
Ok , can you upload what you have tried?

Sign in to comment.

Accepted Answer

Thiago Henrique Gomes Lobato
This should do:
rng(42)
n = 3;
x = rand(n,1);
A = ones(n,n+1);
Differences = x-x';
for idx=2:n+1
A(:,idx) = A(:,idx-1).*Differences(:,idx-1);
end
x
A
x =
0.3745
0.9507
0.7320
A =
1.0000 0 0 0
1.0000 0.5762 0 0
1.0000 0.3575 -0.0782 0

More Answers (1)

Bruno Luong
Bruno Luong on 19 Jul 2020
Edited: Bruno Luong on 19 Jul 2020
n = 3;
x = rand(n+1,1);
A = cumprod([ones(size(x)), (x-x(1:end-1).')], 2)
  1 Comment
madhan ravi
madhan ravi on 19 Jul 2020
Edited: madhan ravi on 19 Jul 2020
But why though? It’s pretty obvious it’s a homework question? It’s not a homework solving contest XD.

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!